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Thursday, 16 May 2013

C code for Detail Cocomo Model

//C program to calculate effort, development time, productivity and average staff required in Detail cocomo model//

#include<stdio.h>
#include<conio.h>
#include<math.h>

int fround(float x)
{
  int a;
  x=x+0.5;
  a=x;
  return(a);
}

void main()
{
  float table[3][4]={3.2,1.05,2.5,0.38,3.0,1.12,2.5,0.35,2.8,1.20,2.5,0.32};
  int i,j,size,model,rating,S;
  char mode[][15]={"Organic","Semi-Detached","Embedded"};
  char driver[15][6]={"RELY","DATA","CPLX","TIME","STOR","VIRT","TURN","ACAP","AEXP","PCAP",
  "VEXP","LEXP","MODP","TOOL","SCED"};
  float effort,EAF,a,time,staff,productivity;
  float costdrivers[15][6]={
                {0.75,0.88,1,1.15,1.40,-1},
                {-1,0.94,1,1.08,1.16,-1},
                {0.70,0.85,1,1.15,1.30,1.65},

                {-1,-1,1,1.11,1.30,1.66},
                {-1,-1,1,1.06,1.21,1.56},
                {-1,0.87,1,1.15,1.30,-1},
                {-1,0.87,1,1.07,1.15,-1},

                {1.46,1.19,1,0.86,0.71,-1},
                {1.29,1.13,1.00,0.91,0.82,-1},
                {1.42,1.17,1,0.86,0.70,-1},
                {1.21,1.10,1,0.90,-1,-1},
                {1.14,1.07,1,0.95,-1,-1},

                {1.24,1.10,1.00,0.91,0.82,-1},
                {1.24,1.10,1,0.91,0.83,-1},
                {1.23,1.08,1,1.04,1.10,-1}
                };

  float mp[6][5]={
            {0.06,0.16,0.26,0.42,0.16},
            {0.06,0.16,0.24,0.38,0.22},
            {0.07,0.17,0.25,0.33,0.25},
            {0.07,0.17,0.24,0.31,0.28},
            {0.08,0.18,0.25,0.26,0.31},
            {0.08,0.18,0.24,0.24,0.34}
          };
  float tp[6][5]={
            {0.10,0.19,0.24,0.39,0.18},
            {0.12,0.19,0.21,0.34,0.26},
            {0.20,0.26,0.21,0.27,0.26},
            {0.22,0.27,0.19,0.25,0.29},
            {0.36,0.36,0.18,0.18,0.28},
            {0.40,0.38,0.16,0.16,0.30}
          };

  char phases[5][30]={"Planning and Requirements","System Design","Detail Design","Module Code and Test","Integration and Test"};
  clrscr();
  printf("\nEnter the size of project : ");
  scanf("%d",&size);
  if(size>=2 && size<=50)
    model=0;
  else if(size>50 && size<=300)
    model=1;
  else if(size>300)
    model=2;
  printf("\nMode = %s",mode[model]);
  EAF=1;
  for(i=0;i<15;i++)
  {
    do
    {
    printf("\nRate cost driver %s on scale of 0-5 : ",driver[i]);
    printf("\n0-Very Low\t1-Low\t2-Nominal\t3-High\t4-Very High\t5-Extra High\n");
    scanf("%d",&rating);
    a=costdrivers[i][rating];
    if(a==-1)
    {
       printf("\nNo value exist for this rating..Enter another rating...\n");
    }
    }while(a==-1);
    EAF=EAF*a;
  }
  printf("\nEAF = %f",EAF);

  effort=(table[model][0]*pow(size,table[model][1])) * EAF;
  time=table[model][2]*pow(effort,table[model][3]);
  staff=effort/time;
  productivity=size/effort;

  printf("\n\nEffort = %f Person-Month",effort);
  printf("\nDevelopment Time = %f Months",time);
  printf("\nAverage Staff Required = %d Persons",fround(staff));
  printf("\nProductivity = %f KLOC/Person-Month",productivity);
  printf("\n\n");

  if(model==0)
  {
    printf("\nEnter Ogranic - Small(0) or Medium(1) : ");
    scanf("%d",&S);
  }
  else if(model==1)
  {
    printf("\nEnter Semi-Detached - Medium(2) or Large(3) : ");
    scanf("%d",&S);
  }
  else if(model==2)
  {
    printf("\nEnter Embedded - Large(4) or Extra Large(5) : ");
    scanf("%d",&S);
  }
  printf("\n\nPhase-wise Distribution of Effort is :\n\n");
  for(i=0;i<5;i++)
  {
     printf("\n%s Phase  =  ",phases[i]);
     printf("%f",effort*mp[S][i]);
  }
  printf("\n\nPhase-wise Distribution of Development Time is :\n\n");
  for(i=0;i<5;i++)
  {
     printf("\n%s Phase  =  ",phases[i]);
     printf("%f",time*tp[S][i]);
  }
getch();
}

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