C program that prints X with probability=0.1, Y with probability=0.3, and Z with probability=0.6

/*This program uses random function to generate random number which help
to calculate a probability of a occurrence of the specific condition. */

Source Code in java (ProbGen.java)

import java.util.Random;

class ProbGen

{

public static void main(String ar[])

{

/*

no_x,no_y,no_z are variables to count the no. of x,y and

z respectevily in the output of the test.

*/

int i,no_x=0,no_y=0,no_z=0;

float rand=0;

for(i=0;i<10000;i++)

{

/*

Random.nextFloat() generates a float from 0.0 (inlcusive)

to 1.0 (exclusive).

*/

rand = new Random().nextFloat(); // [0;1)

if(rand>=0.0 && rand<0.1)

{

System.out.print("x");

no_x++;

}

else if(rand>=0.1 && rand<0.4)

{

System.out.print("y");

no_y++;

}else

{

System.out.print("z");

no_z++;

}

}

System.out.println("\nNo of x="+no_x+"\nNo of y="+no_y+"\nNo of Z="+no_z);

}

}

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Source Code in C

#include <stdlib.h>

#include <stdio.h>

#include<conio.h>

int main(void)

{

int i,no_x=0,no_y=0,no_z=0;

float p;

clrscr();

printf("Ten random numbers from 0 to 99\n\n");

for(i=0; i<10000; i++)

{

p= (float)(rand() % 10)/10;

if(p>=0 && p<0.1)

{printf("x"); no_x++;}

else

if(p>=0.1 && p<=0.4)

{printf("y");no_y++;}

else

{printf("z");no_z++;}

}

printf("\nNo fo x=%d\No of y=%d\nNo of z=%d",no_x,no_y,no_z);

getch();

return 0;

}